x^2-x=2x^2-3x+35

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Solution for x^2-x=2x^2-3x+35 equation: 



x^2-x=2x^2-3x+35

We move all terms to the left:

x^2-x-(2x^2-3x+35)=0

We add all the numbers together, and all the variables

x^2-1x-(2x^2-3x+35)=0

We get rid of parentheses

x^2-2x^2-1x+3x-35=0

We add all the numbers together, and all the variables

-1x^2+2x-35=0

a = -1; b = 2; c = -35;
Δ = b2-4ac
Δ = 22-4·(-1)·(-35)
Δ = -136
Delta is less than zero, so there is no solution for the equation

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